150k views
16 votes
If ANQZ - ACBK, find BK. *

O BK = 39
O BK = 16
O BK = 65
O BK = 27


If ANQZ - ACBK, find BK. * O BK = 39 O BK = 16 O BK = 65 O BK = 27 ​-example-1

1 Answer

4 votes

9514 1404 393

Answer:

(c) BK = 65

Explanation:

Corresponding sides are proportional in similar triangles, so ...

ZT/ZQ = KF/KB

27/(2x +7) = 45/(4x+1)

27(4x+1) = 45(2x +7) . . . cross-multiply

3(4x +1) = 5(2x +7) . . . . divide by 9

12x +3 = 10x +35 . . . . . eliminate parentheses

2x = 32 . . . . . . . . . . . . . subtract 10x+3

x = 16 . . . . . divide by 2

Then the length of BK is ...

BK = 4x+1 = 4·16 +1

BK = 65

User Zarah
by
4.6k points