Question

A ball is thrown with an initial speed of 10. meters

per second. At what angle above the horizontal
should the ball be thrown to reach the greatest
height?
(1) 0° (3) 45°
(2) 30.° (4) 90.°

Answer 1

(4) 90.°

Step-by-step explanation:

The maximum height reached by the ball depends on the vertical velocity of the ball: the greater the vertical velocity of the ball, the higher the ball will go.

The vertical component of the velocity of the ball is given by:

`v_y = v_0 sin \theta`

where

`v_0 = 10 m/s` is the initial speed of the ball

`\theta` is the angle at which the ball is thrown

Therefore,
`v_y` will be maximum when
`sin \theta =1`. And by solving this equation, we find that the angle that satisfies this condition is
`\theta=90^(\circ)`, which corresponds to throwing the ball straight up.

Answer 2

It should be thrown at a 90 degree angle (4) which is the same as throwing it straight up