Question

The volume of 6.00M HCl needed to make 319 ml of 6.80M HCl

Answer 1

The mole number of the solute after dilution is constant. So the mole number of 319 ml of 6.80 M HCl is 6.80*319*10^(-3)=2.17 mol. So the  volume of 6.00 M HCl needed is 2.17/6.00=0.362 L=362 ml.

Answer 2

Answer : The volume of 6.00 M HCl needed are, 361.5 ml

Solution :

According to the neutralization law,

`M_1V_1=M_2V_2`

where,

`M_1` = molarity of HCl solution = 6.00 M

`V_1` = volume of HCl solution = ?

`M_2` = molarity of another HCl solution = 6.80 M

`V_2` = volume of another HCl solution = 319 ml

Now put all the given values in the above law, we get the volume of HCl solution.

`(6.00M)* V_1=(6.80M)* (319ml)`

`V_1=361.5ml`

Therefore, the volume of 6.00 M HCl needed are, 361.5 ml