Cao(s) + h2o(l) = ca(oh)2(s) what mass of slaked lime can be produced from a mixture of 28.4 g of cao and 13.3g of h20

Question

asked Jan 24, 2016 4.5k views

1 Answer

Martijn Courteaux · Answer 1 · 2016-01-30T19:27:51+0000

The equation given is already balanced. The mol number of CaO is 28.4/56=0.51 mol. The mol number of H2O is 13.3/18=0.74 mol. So the slaked lime being produced is 0.51 mol equals to 37.74 g.

Cao(s) + h2o(l) = ca(oh)2(s) what mass of slaked lime can be produced from a mixture of 28.4 g of cao and 13.3g of h20

Please log in or register to add a comment.

Please log in or register to answer this question.

1 Answer

Please log in or register to add a comment.

Related questions

Categories

Other Questions