Register
How much iron is present in 4.64 g of iron(iii) oxide? answer in units of g
84.6k views
2 votes
How much iron is present in 4.64 g of iron(iii) oxide? answer in units of g

User Quan
by
8.1k points

1 Answer

6 votes
The formula of iron(iii) oxide is Fe2O3. The gram formula mass of Fe2O3 is 56*2+16*3=160. And the Fe accounts for 56*2=116 in one molecule. So the iron mass is 4.64/160*116=3.364 g.
User Bnuhero
by
7.9k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Other Questions

How do you balance __H2SO4 + __B(OH)3 --> __B2(SO4)3 + __H2O
Can someone complete the chemical reactions, or write which one do not occur, and provide tehir types? *c2h4+h2o *c3h8 + hcl *c2h2+br2 *c4h10+br2 *c3h6+br2
As an object’s temperature increases, the ____________________ at which it radiates energy increases.
Why is gold preferred as a superior metal over silver and bronze?
Which is an example of an atom? A)the smallest unit of Ne B)the smallest unit of p4 C)the smallest unit of NH3 D)the smallest unit of H2O
Link Copied!