Question

Please solve this proportion with steps (I'm stuck)
(9x+6)/18= (20x+4)/3x

Answer 1

First, distribute your like terms, which in this case is 'x'

you should get (9x+6)/18= 60x + 12

then you have to multiply both sides by 18 to get rid of the fraction

you should then get 9x+6= 1080x + 206

next, subtract 9x from 1080x, you should get 1071x

then subtract 206 on the side the 6 is on and you should get -200=1080x

divide both sides by 1080 and you should get x=0.19

For future preferences use PEMDAS = Parentheses, exponents, multiplication, division, addition, and subtraction. (Yeah, I know I didn't do it in that order)

Answer 2

`(9x+6)/(18)=(20x+4)/(3x)`

Cross multiply. Distribute...

`3x(9x+6)=18(20x+4)\\27x^2+18x=360x+72\\27x^2-342x-72=0\\3x^2-38x-8=0`

OH GOD IT'S A QUADRATIC
(our equation is in ax² + bx + c = 0 form. a=3. b= -38. c= -8.
plug these values into the quadratic formula and simplify.)

`x=(-b\pm√(b^2-4ac))/(2a)=(-(-38)\pm√((-38)^2-4(3)(-8)))/(2(3))=\frac{38\pm√(1444+96)}6\\\\√(1444+96)=√(1540)=√(4*345)=2√(345)\\\\\frac{38\pm2√(345)}6=\boxed{x=\frac{19\pm√(345)}3}`

Approximate values for x: -0.20714 or 12.874