Question

Solve for x: log6(x+29) - log6(x-6) = 2

Answer 1

`log_6(x+29)-log_6(x-6)=2`

`log_6{6^2}=2`

`log_6(x+29)-log_6(x-6)=log_6{6^2}=log_6{36}`

`log_6(x+29)-log_6(x-6)=(log_6(x+29))/(log_6(x-6))=log_6{36}`

`(x+29)/(x-6)=36`

`x+29=36(x-6)`

`x+29=36x-216`

`35x=245`

`x=(245)/(35)=7`

`log_6{36}-log_6{1}=2`