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An experiment produced 0.10 g CO2, with a volume of 0.056 L at STP. If the accepted density of CO2 at STP is 1.96 g/L, what is the approximate percent error?

User Snakey
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2 Answers

3 votes
The experiment result shows that the density of CO2 at STP is 0.1/0.056=1.79 g/L. The percent error equals: |1.79-1.96|/1.96*100%=8.67%. So the answer is 8.67%.
User Neon Flash
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7 votes
The experimental density is calculated as:
(0.10)/(0.056) = 1.79 g/L. To calculate the percent error, we use the equation:

(|Experimental-Theoretical|)/(Theoretical)=(|1.79-1.96|)/(1.96)=0.0889
Therefore, the % error is 8.89%
User Tudor Zgureanu
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