Question

What are the coordinates of the center of a circle whose equation is:(20 - 6)2 + (y – 2)?81Center:

Answer 1

The equation of a circle located at a distance (a,b) from the origin is given by

`y=(x-a)^2+(y-b)^2=r^2`

Given:

`\begin{gathered} y=(x-6)^2\text{ + (}y-2)^2\text{ = 81} \\ y=(x-6)^2\text{ + (}y-2)^2\text{ = }9^2 \end{gathered}`

To get the coordinates, we will have to compare the given equation to the equation of the

circle

Upon comparing the terms and coefficient,

a = 6

b= 2

r = 9

Hence the center of the circle is (6,2)

radius = 9