Question

H(x)=2x²+x-10
2x²+x-10=0

Answer 1

`2 x^(2) +x-10=0 \\ \\ (2x+5)(x-2)=0 \\ \\ x_(1) =- (5)/(2) \\ x_(2) =2`

Answer 2

h(x)=2x2+x-10

2x²+x-10=0

(2x+5)(x-2)

x=-5/2
x=2


1)

h(x)=2x²+x-10
h(-5/2)= 2(-25/4)+[-5/2]-10
h(-5/2)=-25




2).

h(x)=2x²+x-10
h(2)=2(2)²+2-10
h(2)=8+(-8)
h(2)=0