Question

Determine the potential difference between two charged parallel plates that are 0.50 cm apart and have an electric field strength of 9.0 V/cm.

Answer 1

`E = (V)/(r) \\ V = (E)/(r) \\ V = (9.0V/cm)/(0.5cm) \\ V = 18V`

Answer 2

If the field strength between the plates is 9 volts per cm, then over a path of 1/2cm parallel to the field, the potential changes by (1/2) x (9 volts) = 4.5 volts.