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The point between p and k that is four times as far from p as it is k

The point between p and k that is four times as far from p as it is k-example-1
User ToddJCrane
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3.0k points

1 Answer

21 votes
21 votes

Equations

Let's call

x = distance of the required point to the point P

The distance from P to K is 5 - (-2) = 7. This means the distance from the required point to K is (7 - x).

Our point is located 4 times as far from P than from K, thus:

4(7 - x) = x

Operating:

28 - 4x = x

Adding 4x:

28 = 5x

Dividing by 5:

x = 28/5 = 5.6

The required point is located at -2 + 5.6 = 3.6

Checking the distances:

3.6 - (-2) = 5.6

7 - 5.6 = 1.4

It can be verified that 5.6 is four times 1.4, thus

x = 5.6

User Yuyu
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2.9k points