Question

What is the equation of the line that passes through the points (2,1) and (-4,6)

Answer 1

`m = (y_2 - y_1)/(x_2 - x_1) = (6 - 1)/(-4 - 2) = (5)/(-6) = -(5)/(6) \\\\y - y_1 = m(x - x_1) \\y - 1 = -(5)/(6)(x - 2) \\y - 1 = -(5)/(6)(x) - (5)/(6)(-2) \\y - 1 = -(5)/(6)x - (-1(2)/(3)) \\y - 1 = -(5)/(6)x + 1(2)/(3) \\y = -(5)/(6)x + 2(2)/(3)`