3/4 y+ 1/3(y-4) =y+1 / 7

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asked Aug 17, 2016 194k views

2 Answers

Fuentesjr · Answer 1 · 2016-08-23T23:45:16+0000

³/₄y + ¹/₃(y - 4) = y + ¹/₇
³/₄y + ¹/₃(y) + ¹/₃(-4) = y + ¹/₇
³/₄y + ¹/₃y + (-1¹/₃) = y + ¹/₇
³/₄y + ¹/₃y - 1¹/₃ = y + ¹/₇
1¹/₁₂y - 1¹/₃ = y + ¹/₇
- y - y
¹/₁₂y - 1¹/₃ = ¹/₇
+ 1¹/₃ + 1¹/₃
12 · ¹/₁₂y = 1¹⁰/₂₁ · 12
y = 17⁵/₇

3/4 y+ 1/3(y-4) =y+1 / 7

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