Question

while on a luge run in the olympics the sled (mass=157 kg) rounds a horziontal curve of radius 5.8m with a speed of 18.5 m/s assuming there is no friction what is the normal force exerted by the track on the sled

Answer 1

In a circular motion the normal force is also called centripetal force. The centripetal force is given by:

`F=(mv^2)/(r)`

where m is the mass, v is the velocity and r is the radius.

Plugging the values given we have: