Question

please help How much heat does it take to raise the temperature of 9.0 kg of wood from 12C to 97C? The specific heat of wood is 1.68 kJ/(kgC). Use Q = mc(Tf - Ti). A. 760 kJ B. 1300 kJ C. 180 kJ D. 1500 kJ

Answer 1

Q=mc(Tf-Ti)
= (9Kg)(1.68 KJ/KgC)(97-12)
= 1285.2 KJ
~ 1300 KJ

Answer 2

`Q = 1300 kJ`

Step-by-step explanation:

As we know that heat require to change the temperature of the object is given as

`Q = mC \Delta T`

here we know that

m = mass = 9 kg

C = 1.68 kJ/kg

`\Delta T = 97 - 12`

`\Delta T = 85 degree C`

now from above formula we will have

`Q = 9* 1.68 * 10^3 * 85`

`Q = 1300 kJ`