Question

What is the area of a square with a side of 8x^7 y^3

Answer 1

Area of a square with side s is
`\sf{s^2}`

In your question, the side or s is:
`\sf{8x^7y^3}`

And so the area of a square with that side length would be:


`\sf{(8x^7y^3)^2}`

And using this formula:
`\sf{(a^b)^c =a^(b* c)}`

We get that the area is:


`\sf{(8x^7y^3)^2 = 8^2 x^(7* 2) y^(3* 2)}`

And simplifying that we get the final answer as:


`\huge{\boxed{\bf{Area=64x^(14)y^(6)}}}`