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A law firm has eight male and six female lawyers. A committee of five, two male lawyers and three female lawyers, is to be chosen to represent the firm at a conference. How many committees are possible?

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The number of way we can choose 2 males out of 8 is combinations of:

C(8,2)=7*8/2 =56/(1*2)=28
to choose 3 females out of 6
C(6,3)=6*5*4/(1*2*3)=120/6=20
the number of committees is= 28*20=560
User NetOperator Wibby
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