Question

What is, 7 3/10+6 1/3+2 7/10?

Answer 1

We are going to add 7 3/10 and 2 7/10 first.
`\boxed{\boxed{7 (3)/(10)}}+\boxed{\boxed{2 (7)/(10)}}}=\boxed{\boxed{9 (10)/(10)}}`. Now we are going to add
`\boxed{\boxed{9{ (10)/(10)}}}` by
`\boxed{\boxed{6{ (1)/(3)}}}`.
`\boxed{\boxed{9{ (10*3)/(10*3)}}}=\boxed{\boxed{9{ (30)/(30)}}} \ and \ \boxed{\boxed{6 (1*10)/(3*10)}}}=\boxed{\boxed{6{ (10)/(30)}}}`. Finnally we add.
`\boxed{\boxed{9{ (30)/(30)}}}+{\boxed{\boxed{6{ (10)/(30)}}}=\boxed{\boxed{15 (40)/(30)}}}.`. Last, but not least we simplify,
`\boxed{\boxed{15{ (30:10)/(40:10)}}}=\boxed{\boxed{15 (3)/(4)}}}`. Therefore, your answer is
`\boxed{\boxed{15 (3)/(4)}}}`. Hoped I helped. :)

Answer 2

7 3/10 + 6 1/3 + 2 7/10

First change them to improper fractions

73/10 + 19/3 + 27/10

now find the common denominator which would be 30

73/10 = 219 /30

19/3 = 190/30

27/10 = 81 /30

now add (219 + 190 + 81) = 490/30

now divide 490 ÷ 30 = 16 1/3

Your answer is 16 1/3

Hope this helps. :)