Question

Quadratic Equations: ax^2+bx+c=0

Factor first mult. A and C then use the factors from the answer to add to B
1.) 2b^2+10b+12
2.) 3g^2+8g+4
3.) 4x^2+4x-3
4.) 8b^2-5b-10
5.) 6m^2+7m-3
6.) 10d^2+17d-20
Please Answer ASAP Show ALL WORK

Answer 1

quadratic equaiton is
x=
`(-b- √(b^2-4ac) )/(2a)` or
`(-b+ √(b^2-4ac) )/(2a)`

just subsitute and simplify
I will only do one in detail since it takes some time

so first one2b^2+10b+12
a=2
b=10
c=12
subsitute
x=
`(-10- √(10^2-4(2)(12)) )/(2(2))` or

`(-10+ √(10^2-4(2)(12)) )/(2(2))`
pemdas


`(-10- √(10^2-4(2)(12)) )/(2(2))`
do parenthasees or inside exponents
(10^2-4(2)(12) =(100-96)=4
square root of 4=2
(-10-2)/(2 times 2)=-12/4=-3
if -10+square root then
(-10+2)/(2 times 2)=-8/4=-2
answer is
b=-3 or -2


second one
answer is g=-2 or -2/3


3rd
x=-3/2 or 1/2

4th
b=
`(5- √(345) )/(16)` or

`(5+ √(345) )/(16)`

5th
m=-3/2 or 1/3

6th
d=-5/2 or 4/5