Question

could someone help with the steps! In a survey conducted in an office, 60% of the sample respondents agreed that employees should have flexible working hours. If the margin of error is ±2%, the expected population proportion that wants flexible working hours is between ? % and ? %

Answer 1

58%-62%
just add 2 to 60
and subtract 2 from 60 to find the range of percents

Answer 2

Answer: The expected population proportion that wants flexible working hours is between 58% and 62%.

Explanation:

The margin of error (E) is used to represent the level of accuracy of any random sample.

Confidence interval for population percentage (p):

(p-E, p+E ) , where E is the margin of error ( in percentage.)

Given : The percentage of the sample respondents agreed that employees should have flexible working hours : p = 60%

The margin of error : E= ± 2%

Then , the expected population proportion that wants flexible working hours is between : 60%-2% and 60% +2%

= 58% and 62%.

Hence, the expected population proportion that wants flexible working hours is between 58% and 62%.