Question

Solve the quadratic equation by completing the square form - solution- x=

Answer 1

Given
`x^2-2x-10=0`Solution

`x^2-2x-10=0`

Keep x terms on the left and move the constant to the right side by adding it on both sides

`x^2-2x=10`

Take half of the x term and square it

`(-2*(1)/(2))^2=1`

Then add the result to both sides

`x^2-2x+1=10+11`

Rewrite the perfect square on the left

`(x-1)^2=10+1`

and combine terms on the right

`(x-1)^2=11`

Take the square root of both sides

`\begin{gathered} x-1=\pm√(11) \\ x=1\pm√(11) \\ \end{gathered}`

simplify

`\begin{gathered} x=4.32\text{ \lparen nearest 0.01\rparen} \\ x=-2.32(nearest\text{ 0.01\rparen} \end{gathered}`The final answer