Question

the amount of charge that moves through the filament of a lightbulb in 2.00 s is 2.67 C. what is the current of the lightbulb?

Answer 1

The electric "current" in a conductor is the rate at which
charge flows through it.

Current = (charge) / (time)

Current = (2.67 Coulombs) / (2 seconds) =

1.335 Coulombs per second =

1.335 Amperes