How would you solve 3sin0=sin0-1

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asked Feb 20, 2016 38.3k views

5 votes

How would you solve 3sin0=sin0-1

Mathematics
high-school

Harvinder Singh asked

by Harvinder Singh

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2 Answers

3 votes

3sinΘ = sinΘ - 1
3sinΘ - sinΘ = sinΘ - sinΘ - 1
2sinΘ = -1
2sin 2sin
Θ = -2.864934497

Singer answered Feb 21, 2016

by Singer

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1 vote

I would subtract 1sin(Θ) from each side of the equation.
The equation would then say that 2sin(Θ) = -1 .
I would only have to find angles whose sin is -1/2 ,
and those would be my solutions.

Tai Dao answered Feb 25, 2016

by Tai Dao

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