Break it down.
Hint : Radius is half the diameter, 8 / 2 = 4
Part A:
A = πr^2
A = π(4)^2
A = π16
Part B :
C = πd
C = π8
but its 2in. wide
C = π8 x 2
C = π16
From the previous question, I know the area is π16
A = π16 + C = π16 = π32
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