Register

ΔABC is right-angled at A and |AB|=2|AC|. Prove that |BC|^2=5|AC|^2

ΔABC is right-angled at A and |AB|=2|AC|. Prove that |BC|^2=5|AC|^2
167k views
0 votes
ΔABC is right-angled at A and |AB|=2|AC|. Prove that |BC|^2=5|AC|^2

User Lucas Abbade
by
8.1k points

1 Answer

7 votes

|AB|^2+|AC|^2=|BC|^2\\\\ (2|AC|)^2+|AC|^2=5|AC|^2\\ 4|AC|^2+|AC|^2=5|AC|^2\\ 5|AC|^2=5|AC|^2
User Lostiniceland
by
8.4k points
← Prev Question Next Question →

Related questions

User Toonice
asked Nov 15, 2022 151k views
ΔABC is right-angled at C.If AC=5cm and BC=12cm find the length of AB.​
Toonice asked Nov 15, 2022
by Toonice
8.2k points
1 answer
8 votes
151k views
User Sachin Thapa
asked Jul 12, 2023 118k views
Need help! In ΔABC right angled at A, D and E are points on BC, C such that BC= CD and AD ⊥ BC
Sachin Thapa asked Jul 12, 2023
by Sachin Thapa
8.6k points
1 answer
13 votes
118k views
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!