ΔABC is right-angled at A and |AB|=2|AC|. Prove that |BC|^2=5|AC|^2

asked Jan 14, 2016 167k views

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$|AB|^2+|AC|^2=|BC|^2\\\\ (2|AC|)^2+|AC|^2=5|AC|^2\\ 4|AC|^2+|AC|^2=5|AC|^2\\ 5|AC|^2=5|AC|^2$

Lostiniceland answered Jan 20, 2016

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