Question

Solve for x: 2x^2+4x-16+=0

Answer 1

`2x^2+4x-16=0|:2\\ x^2+2x-8=0\\ \Delta=36\Rightarrow√(\Delta)=6\\ x_1=(-b+√(\Delta))/(2a)\ \vee\ x_=(-b-√(\Delta))/(2a)\\ x_1=2\ \vee\ x_2=-4`

Answer 2

`2x^2+4x-16=0\ /:2\\ \\x^2+2x-8=0\\ \\x^2-2x+4x-8=0\\ \\x(x-2)+4(x-2)=0\\ \\(x-2)(x+4)=0\ \ \ \Leftrightarrow\ \ \ x-2=0\ \ \ \vee\ \ \ x+4=0\\ \\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=2\ \ \ \ \ \ \ \ \ \ \ \ \ \ x=-4`