indentify the vertex and axis of symmetry of each. then sketch the graph-the instructions f(x)=-3(x-3) squareed -4
we have the equation
f(x)=-3(x-3)^2-4
the equation of a vertical parabola in vertex form is equal to
y=a(x-h)^2+k
where
(h,k) is the vertex
The given equation is written in vertex form
so
the vertex is the point (3,-4)
The axis of symmetry in a vertical parabola is equal to the x-coordinate of the vertex
so
axis of symmetry is
x=3
using a graphing tool
see the attached figute
the given equation is
f(x)=-3(x-3)^2-4
the equation in vertex form is
y=a(x-h)^2+k
(h,k) is the vertex
that means
(h,k)=(3,-4)