Question

How many combinations of 3 students can a teacher choose from 32 students?

  A. 96   B. 4960   C. 29,760   D. 32,768

Answer 1

`{32\choose3}=(32!)/(3!*(32-3)!)=(30*31*32)/(6)=4960`

Answer 2

`(32*31*30)/(3*2*1)`

The answer is:
`(29760)/(6)` or
`4960`