Question

What is the area of a rectangle with a length of (x^2-2) and a width of(2x-x+2)

Answer 1

A = lw
A = (x² - 2)(2x - x + 2)
A = (x² - 2)(x + 2)
A = x²(x + 2) - 2(x + 2)
A = x²(x) + x²(2) - 2(x) - 2(2)
A = x³ + 2x² - 2x - 4

Answer 2

The area of a rectangle can be found through the formula
`A=lw`, where l is the length and w is the height. In this situation, the answer can be found by multiplying the length and width provided:


`(x^2-2)*(2x-x+2)`

The distributive property must be applied here:


`(x^2-2)*(2x-x+2) \\ 2x^3-x^3+2x^2-4x+2x-4`

Now simplify by combining like terms:

The area is

`x^3+2x^2-2x-4`