Question

Find the slope of the line containing the pair of points.

(-10,-3) and (-12,-10)
the slope of the line is...........???

Answer 1

`m = (y_2 - y_1)/(x_2 - x_1) = (-10 - (-3))/(-12 - (-10)) = (-10 + 3)/(-12 + 10) = (-7)/(-2) = 3(1)/(2)`

The slope of the line is equal to 3¹/₂.


`y - y_1 = m(x - x_1) \\y - (-3) = 3(1)/(2)(x - (-10) \\y + 3 = 3(1)/(2)(x + 10) \\y + 3 = 3(1)/(2)(x) + 3(1)/(2)(10) \\y + 3 = 3(1)/(2)x + 35 \\y = 3(1)/(2)x + 32`

Answer 2

`\sf~m=(y_2-y_1)/(x_2-x_1)`

(-10, -3), (-12, -10)
x1 y1 x2 y2

Plug in what we know:


`\sf~m=(-10-(-3))/(-12-(-10))`

Subtract:


`\sf~m=(-7)/(-2)`

Divide:


`\sf~m=\boxed{\sf3.5}`