Question

a 16.0g sample of iron was heated from 0 degrees Celsius o 35.0 degrees Celsius.the iron absorbed 246.4J of energy as heat. what is the specific heat of this piece of iron?

Answer 1

Specific heat means the amount heat needed when unit mass of a substrate increase one degree of temperature. So the specific heat = the heat absorbed/(the mass of the substrate * change in temperature) = 264.4/(16*35)=0.472 J/(g*℃）

Answer 2

Answer:
`0.44J/g^0C`

Step-by-step explanation:

Specific heat capacity of a substance is defined as the amount of heat required to raise the temperature of 1g of substance through
`1^0C`

`Q= m* c* \Delta T`

Q= heat gained = 246.4 J

m= mass of the substance = 16 g

c = heat capacity of iron= ? J/g ° C

`\Delta T={\text{Change in temperature}}=(35-0)^oC=35^0C`

`246.4=16g* cJ/g^oC* 35^oC`

`c=0.44J/g^0C`

Thus specific heat capacity of iron is
`0.44J/g^0C`