Register
1. What is the empirical formula for a compound containing 63.8% N and 36.2% O? a. N₂O₅ b. N₂O₃ c. NO₂ d. NO e. N2₂O
45.2k views
0 votes
1. What is the empirical formula for a compound containing 63.8% N and 36.2% O?

a. N₂O₅
b. N₂O₃
c. NO₂
d. NO
e. N2₂O

User Bob Harner
by
8.8k points

1 Answer

2 votes

M\ N_2=28g/mol\\ 63,8\%--28g\\ 100\%--x\\ x=43,89g

43,89g≈44g
44g == 2x 14g (N) + 1x 16x(O)
M N₂O = 44g

User Saeid Mirzaei
by
7.6k points
← Prev Question Next Question →

Related questions

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers

Other Questions

Compare and contrast an electric generator and a battery??
How do you balance __H2SO4 + __B(OH)3 --> __B2(SO4)3 + __H2O
Can someone complete the chemical reactions, or write which one do not occur, and provide tehir types? *c2h4+h2o *c3h8 + hcl *c2h2+br2 *c4h10+br2 *c3h6+br2
As an object’s temperature increases, the ____________________ at which it radiates energy increases.
What is the evidence of a chemical reaction when the fireworks go off
Link Copied!