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The diagram below shows the contents of a jar from which you select marbles at random.

a. What is the probability of selecting a red marble, replacing it, and then selecting a blue marble? Show your work.
b. What is the probability of selecting a red marble, setting it aside, and then selecting a blue marble? Show your work.
c. Are the answers to parts (a) and (b) the same? Why or why not?

The diagram below shows the contents of a jar from which you select marbles at random-example-1
User Arvind
by
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1 Answer

6 votes
So,

There are 4 red marbles.
There are 7 blue marbles.
There are 5 green marbles.
There are 16 marbles in total.

a.
Answer = (probability of selecting a red marble)(probability of selecting a blue marble)
First, the probability of selecting a red marble.

(4)/(16) \ or\ (1)/(4)

Next, the probability of selecting a blue marble.

(7)/(16)

Multiply the probabilities together.

(1)/(4) * (7)/(16) = (7)/(64)
That is the probability for event a.


b.
Answer = (probability of selecting a red marble)(probability of selecting a blue marble)
First, the probability of selecting a red marble.

(4)/(16) \ or\ (1)/(4)

Next, the probability of selecting a blue marble WITH A RED MARBLE REMOVED.

(7)/(15)

Multiply the probabilities together.

(1)/(4) * (7)/(15) = (7)/(60)
That is the probability for event b.

c.
Obviously:

(7)/(64) \\eq (7)/(60)
So the answer is no.
User Dietr
by
7.6k points
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