Question

a sample of ore is found to be 0.0051% silver and 0.048% diamond what is the percentage of matter in the ore that is neither silver nor diamond

Answer 1

% silver in the ore = 0.0051%

% diamond in the ore = 0.048%

The percentage of the matter in the ore that is neither silver nor diamond can be calculated below

`\begin{gathered} \text{silver}=\text{ 0.0051\%} \\ \text{diamond}=0.048\text{ \%} \\ \text{neither silver nor diamond = 100-0.0051-0.048 = }99.9469\text{ \%} \end{gathered}`