Question

You kick a ball with a speed of 14 m/s at an angle of 51 degrees. How far away does the ball land?

A. 21.3 m
B. 19.6 m
C. 1.8 m
D. 3.96 m

Answer 1

d may be the correct answer because speed is very low so ball should cover less distance  but angle is not very high so it can cover little much distance

Answer 2

Answer: The ball will land at 19.6 m

Step-by-step explanation:

To calculate the horizontal range of the ball, we use the formula:

`R=(v^2\sin 2\theta)/(g)`

where,

v = velocity of the ball = 14 m/s

`\theta` = angle at which the ball is thrown = 51°

g = acceleration due to gravity =
`9.8m/s^2`

Putting values in above equation, we get:

`R=((14)^2* \sin (2* 51))/(9.8)\\\\R=19.6m`

Hence, the ball will land at 19.6 m