-- The difference of 2 logs is the log of the quotient of their arguments.
log(11) - log(6) = log(11/6)
-- 1/3 of the log of something is the log of its cube root.
1/3 log(8) = log(∛8) = log(2)
and
1/3 log(729) = log(∛729) = log(9)
-- If a bunch of logs all have the same base, then their sum
is the log of the product of the arguments. So ...
log(11) - log(6) + 1/3 log(8) + 1/3 log(729) =
log(11/6 times 2 times 9) =
log( 11*18 / 6 ) = log(33)
log(33) = about 1.519 (rounded)
============================================
The other way:
log(11) = 1.0414
-log(6) = -0.7782
log(8) = 0.9031
1/3(0.9031) = 0.3010
log(729) = 2.8627
1/3(2.8627) = 0.9542
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Adum up: 1.5184
(Note: Everything is rounded.)