Question

How Do You Do:
2(n-7)+3=9

And:
4h+7h-16=6

Answer 1

2 (n-7) +3=9 remove ( ) and distribute 2n-14+3=9 combine like terms 2n-11=9 add 11 to both sides 2n=20 n=10 4h+7h-16=6 combine like terms 11h-16=6 add 16 to both sides 11h=22 h= 2 hope this helps

Answer 2

To solve equations with variables, we use inverse operations.
Inverse operations are operations that cancel each other out.
(plus and minus, multiply and divide)

Say we had
`x-3=6`.
According to the addition property of equality, we could add 3 to each side of that equation and it would still be equal.

`x-3+3=6+3`
This would cancel out the -3 and leave us with just
`x=9`.

Question 1) Solve
`2(n-7)+3=9`.

Let's just start cancelling things out. Doesn't matter what order.


`2(n-7)+3=9 \\ 2(n-7)+3-3=9-3\\ 2(n-7)=6 \\\\\ \frac{2(n-7)}2=\frac{6}2\\n-7=3\\\\n-7+7=3+7\\\boxed{n=10}`

Question 2) Solve
`4h+7h-16=6`.

You can add
`4h` and
`7h` together to get
`11h`. The h acts sort of like a unit in that case, like 4 feet + 7 feet = 11 feet.


`11h-16=6\\11h-16+16=6+16\\11h=22\\\\(11h)/(11)=(22)/(11)\\\boxed{h=2}`