36.5k views
0 votes
The perimeter of a rectangular playing field is 244 feet. If its length is 2 feet longer than twice its width, what are the dimensions of the field?

User LeMoisela
by
7.3k points

2 Answers

6 votes
The perimeter (P) of a polygon is all the values of all the sides added together. (Length+Length+Width+Width) If the length (L) of the rectangle is 2 feet longer than twice the width (W), then L=2W+2. So now the perimeter is 2W+2+2W+2+W+W = P. This simplifies to 6W+4=P. If we know the perimeter is 244, then 6W+4=244. Then subtract four and divide by 6. W=40. If L=2W+2, then L=2(40)+2, or L=82. SO.....
The width is 40 feet
The length is 82 feet

User Stefan Moser
by
7.9k points
5 votes
Peri = 2A+2B

244 = 2(2+2x) + 2(x)
User Ynux
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories