Question

How to solve 9x+5=28
-3x-10y=-26 by Elimination

Answer 1

9x + 5 = 28
- 5 - 5
9x = 23
9 9
x = 2⁵/₉

-3(2⁵/₉) - 10y = -26
-7²/₃ - 10y = -26
+ 7²/₃ + 7²/₃
-10y = -18¹/₃
-10 -10
y = 1⁵/₆
(x, y) = (2⁵/₉, 1⁵/₆)

Answer 2

so elimination
I assume that you meant to write
9x+5y=28 and not 9x+5=28
so

elimination is basically eliminating values

9x+5y=28
-3x-10y=-26
we can either cancel out the x terms or the y terms, I will cancel out the y terms

9x+5y=28
multipy both sides by 2
18x+10y=56
add to other equation


18x+10y=56
-3x-10y=-26 +
15x+0y=30
15x=30
divide both sides by 15
x=2

subsitute

9x+5y=28
9(2)+5y=28
18+5y=28
subtract 10 from both sides
5y=10
divide both sides by 5
y=2


x=2
y=2