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Find the area of a rectangle whose sides mesure (4x+3) and (2x-1)
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Find the area of a rectangle whose sides mesure (4x+3) and (2x-1)

User Sch
by
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2 Answers

2 votes
A = lw
A = (4x + 3)(2x - 1)
A = 8x² - 4x + 6x - 3
A = 8x² + 2x - 3
User Honza
by
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0 votes
We can't find the exact area of this rectangle without knowing x. However, in terms of x, we can expand (4x+3)(2x-1) to get
8x^2+2x-3 as the area in terms of x.
User Jlodenius
by
8.4k points
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