Question

what is the equation of the line that's passes through (0,3) and (7,0) ? y=3/7x-3y=3/7x+3y=-3/7x+3y=-3/7x-3

Answer 1

Given: two points (0,3) and (7,0)

The equation of line in slope intercept form is ,

`y=mx+c\ldots(1)`

To find the slope,

`\begin{gathered} m=(y_2-y_1)/(x_2-x_1) \\ (x_(1,)y_1)=(0,3) \\ (x_(2,)y_2)=(7,0) \\ m=(0-3)/(7-0) \\ m=(-3)/(7) \end{gathered}`

Now the equtaion of required line passing through points (0,3) and (7,0)

from equation (1)

`\begin{gathered} y=mx+c \\ y=(-3)/(7)x+c\ldots..(2) \end{gathered}`

Now to find the value of y-intercept c put the point (0,3) in equation (2)

`\begin{gathered} y=(-3)/(7)x+c \\ (x,y)=(0,3) \\ 3=(-3)/(7)(0)+c \\ c=3 \end{gathered}`

Hence, the equation of line is,

`y=(-3)/(7)x+3`

Answer: Option 3) is correct

y=-3/7x+3