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If sin Θ = -square root3/2 and π < Θ < 3pi/2 , what are the values of cos Θ and tan Θ

User Redronin
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π < θ < 3pi/2, so θ ∈ 3 quadrant,
so cosθ<0, tg θ>0

we know that sin²θ+cos²θ=1

cosθ=-√(1-sin²θ)=-√1-
(( √(3) )/(2))²=-√(1-
(3)/(4))=- √0.25=- 0.5
tgθ=
(sin \alpha )/(cos \alpha )= -
( √(3) )/(2): (- 0.5)=√3


P.s. θ=
\alpha, i can't put θ in formula, sorry










User Federico Dorato
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