Question

I need help especially on section C . I want to see the graph please explain.

Answer 1

Plot the following points for the table,

x = 0, 1, 4, 8, 12, 16

`\begin{gathered} f(x)=4-x^{(3)/(2)} \\ \\ f(0)=4-0^{(3)/(2)} \\ f(0)=4 \\ \text{First point }(0,4) \\ \\ f(1)=4-1^{(3)/(2)} \\ f(1)=4-1 \\ f(1)=3 \\ \text{Second point }(1,3) \\ \\ f(4)=4-4^{(3)/(2)} \\ f(4)=4-\sqrt[]{4^3} \\ f(4)=4-\sqrt[]{64} \\ f(4)=4-8 \\ f(4)=-4 \\ \text{Third point }(4,-4)_{} \\ \\ f(8)=4-8^{(3)/(2)} \\ f(8)=4-\sqrt[]{8^3} \\ f(8)\approx-18.62 \\ \text{Fourth point }(8,-18.63) \\ \\ f(12)=4-12^{(3)/(2)} \\ f(12)=4-\sqrt[]{12^3} \\ f(12)\approx-37.57 \\ \text{Fifth point }(12,-37.57) \\ \\ f(16)=4-16^{(3)/(2)} \\ f(16)=4-\sqrt[]{16^3} \\ f(16)=-60 \\ \text{Sixth point }(16,-60) \end{gathered}`

The table therefore is

The graph f(x) is