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What is the range of possible values for x?

What is the range of possible values for x?-example-1
User Nojhan
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The minimum value for 2x is 0
the maximum value is achieved when A, D and C are collinear and the quadrilateral ABCD becomes an isosceles triangle ABC
base AB = 52 and vertical angle 2x + 34°

For the sine law
(sin 2x)/22 = (sin ADB)/AB
(sin 34°)/30 = (sin BDC)/BC

is given that AB = BC, and sin ADC = sin BDC because they are supplementary, so from
(sin ADC)/AB = (sin BDC)/BC

it follows
(sin 2x)/22 = (sin 34°)/30

sin 2x = 22 (sin 34°)/30

2x = asin(22 (sin 34°)/30) ≈ 24.2°

x = 0.5 asin(22 (sin 34°)/30) ≈ 12.1°

0 < x < 12.1°
User BPeter
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