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2log base of 4 x+ log base of 4 (x-1)=1

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First, let's review a couple of basics:

2 x log (something) is the same as log(something²)

The sum of the logs of 2 numbers is the same as the log of their product.

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So 2 log₄(x) = log₄(x²)

From the given equation: log₄(x²) + log₄(x-1) = 1

Sum of logs = log of the product: log₄( [x] [x-1] ) = 1

Raise 4 to the power of each side: (x) (x-1) = 4

Eliminate parentheses on the left: x² - x = 4

Subtract 4 from each side: x² - x - 4 = 0

Mash this through the quadratic formula, and you have

x = 0.5 + 0.5√17 = 2.562 (rounded)

x = 0.5 - 0.5√17 = -1.562 (rounded)


User Ashraf Purno
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