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What is the product of 
k^(3) + 9k^(2) + 3 and 
7k^(2) - 5?

1 Answer

5 votes


(k³+9k²+3)(7k²-5)=

=·7k²+·(-5)+9k² · 7k²+9k² ·(-5)+ 7k²+3·(-5)=

=7k^5-5k³+63k^4-45k²+21k²-15=

=7k^5+63k^4-5k³-24k²-15

User Palerdot
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