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21k^2+4=19k solve for k
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21k^2+4=19k solve for k

User Yoel
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21k^2+4=19k\\ 21k^2-19k+4=0\\ 21k^2-7k-12k+4=0\\ 7k(3k-1)-4(3k-1)=0\\ (7k-4)(3k-1)=0\\ k=(4)/(7) \vee k=(1)/(3)
User Eric Smalling
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