Question

If f(x)=x^2+3 and g(x)= -x-1 find the value of:

1. (g+f)(2)

2. (f/g)(1)

3. (g-f)(6)

Answer 1

`f(x)=x^2+3 \\ g(x)= -x-1 \\ 1. (g+f)(2)=g(2)+f(2)=(-x-1)+ (x^(2) +3)= x^(2) -x+2= (2)^(2) -(2)+2=4 \\ 2. (f/g)(1)=(f(1))/(g(1))= (x^2+3)/(-x-1) = ((1)^2+3)/(-(1)-1) = (4)/(-2) =-2`

`3. (g-f)(6) =g(6)-f(6)=(-x-1)-( x^(2) +3)=- x^(2) -x-4 \\ =- (6)^(2) -(6)-4=-46`