Question

How would I solve these? 

(-3xy)³ (-x³)

and

(-9b²a³)² (3³b)²

Answer 1

`(-3xy)^3(-x^3)=(-3)^3x^3y^3\cdot(-x^3)=-27x^3y^3\cdot(-x^3)=27x^6y^3\\\\\\(-9b^2a^3)^2\cdot(3^3b^2)^2=(-3^2a^3b^2)^2\cdot(3^3b^2)^2=3^(2\cdot2)a^(3\cdot2)b^(2\cdot2)\cdot3^(3\cdot2)b^(2\cdot2)\\\\=3^4a^6b^4\cdot3^6b^4=3^(4+6)a^6b^(4+4)=3^(10)a^6b^8`

Answer 2

`(-9b^2a^3)^2 \cdot (3^3b)^2 = (-9)^2\cdot(b^2)^2 \cdot (a^3)^2 \cdot (3^3)^2\cdot (b)^2 = \\ \\= 81\cdot b^4\cdot a^6 \cdot 3^6\cdot b ^2 = 3^4 \cdot a^6 \cdot b^4\cdot 3^6\cdot b ^2 =\\ \\= 3^(4+6) \cdota^(6) \cdot b ^(4+2) = 3^(10) \cdot a^(6) \cdot b ^6`